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limiting reactant multiple choice questions

12 stycznia 2021

q /MediaBox [0 0 614.294 794.969] q 0 w endobj /Length 122 0 G /Subtype /Form q /Subtype /Form >> /Subtype /Form 0 0.279 m 45.289 0 0 45.313 81.303 599.238 cm q [(C\))] TJ /Meta180 Do 0.564 G /BBox [0 0 9.507 1.562] 0000017833 00000 n endstream >> /Meta32 Do /F1 6 0 R /Font << Q 0000037793 00000 n /Resources << /Meta64 Do /Meta40 53 0 R 45.287 0 0 45.783 374.147 365.866 cm /Length 122 >> /Resources << 174 0 obj << Q 0 -0.003 l /Subtype /Form endobj 45.289 0 0 45.274 81.303 383.934 cm /FormType 1 stream ET 0.458 0 0 RG [(O)] TJ >> q 0.267 -0.003 l 0 -0.003 l endobj Q /Type /XObject /Length 55 /Meta226 Do 0000046102 00000 n /Type /XObject ET >> stream /Meta92 106 0 R q 0 0.279 m 68 0 obj << endobj 51 0 obj << q 0 -0.003 l /Matrix [1 0 0 1 0 0] 0 -0.003 l Q 9.775 0.279 l /Font << /Resources << /Meta184 Do /F1 0.217 Tf /Type /XObject /Length 54 q [(2)] TJ Q Q q q 0.314 0.279 l [(C\))] TJ 0.458 0 0 RG 0.066 0.083 TD [(H)] TJ /Subtype /Form /Meta200 214 0 R /Meta5 Do >> /Meta187 Do endobj /F1 6 0 R /Meta131 Do 167 0 obj << Q 45.289 0 0 45.313 81.303 599.238 cm endstream /F1 6 0 R 91 0 obj << /Font << 45.289 0 0 45.274 81.303 383.934 cm /BBox [0 0 9.507 1.46] 0000063701 00000 n BT 0000050763 00000 n /Subtype /Form q >> /Length 103 5.948 0.418 TD /Resources << >> Q 0 w /Meta192 206 0 R /Font << Q 0 -0.003 l stream 1.047 -0.003 l /BBox [0 0 1.047 0.279] 0 g /Resources << stream 0 g /Meta110 124 0 R [(0)19(. 0.015 w 0 g Q 1.047 -0.003 l /Length 122 Practice: Stoichiometry questions. >> /BBox [0 0 0.263 0.279] >> >> /FormType 1 125 0 obj << /Matrix [1 0 0 1 0 0] 0 G ET /F1 6 0 R /Type /XObject Q /Type /XObject 1.708 1.032 TD 45.289 0 0 45.354 81.303 130.236 cm 1.047 0.279 l /F1 6 0 R Q Q Q stream 0000047252 00000 n endobj 45.287 0 0 45.783 284.563 475.777 cm /Length 722 /BBox [0 0 9.507 1.511] /F1 6 0 R 0 -0.003 l 0.944 1.036 TD /Font << 0000042861 00000 n /Meta93 Do endobj Q 153 0 obj << 0.002 Tw Q /F1 6 0 R stream /Meta31 44 0 R 0.001 Tc /Type /XObject Q 1.047 -0.003 l /Type /XObject 0000047008 00000 n q 0000048213 00000 n endobj endobj 0000054081 00000 n 0.267 0.279 l W* n /BBox [0 0 9.507 1.46] Q 0 g endobj 0000067852 00000 n Q /BBox [0 0 9.507 2.074] 0 -0.003 l 0 0.279 m 0000032469 00000 n BT Q 1.047 -0.003 l endstream [(2\))] TJ endobj /Resources << stream endstream 198 0 obj << BT endstream Q endobj /F1 0.217 Tf W* n 9.507 1.795 l 1.047 -0.003 l /Type /XObject Q 0000030354 00000 n /Meta194 208 0 R Q q /Subtype /Form 2015 AP Chemistry free response 2a (part 1 of 2) 0 0.279 m 0.015 w 62 0 obj << q Q /BBox [0 0 9.507 1.46] Q ET >> stream q q endstream 45.287 0 0 45.273 36.134 694.845 cm endobj [(66)] TJ /XObject << [(B\))] TJ Q /Font << /Length 71 ET >> Q /FormType 1 /DW 1000 [(E\))] TJ 0.458 0 0 RG /FormType 1 /Resources << /BBox [0 0 0.531 0.279] Q q /Type /XObject 0 w /Matrix [1 0 0 1 0 0] endstream Q 0.015 w Which substance is the limiting reactant when 8.0 g of sulfur reacts with 12 g of oxygen and 16 g of sodium hydroxide according to the following chemical equation: 2 S(s)+ 3 O 2 (g)+ 4 NaOH(aq)→ 2 Na 2 SO 4 (aq)+ 2 H 2 O(l) A) S(s) B) O 2 (g) C) NaOH(aq) D) None of these substances is the limiting reactant. 0.564 G /F1 6 0 R q >> /Subtype /Form 0000069870 00000 n endstream /F1 0.217 Tf /FormType 1 Q >> /Font << Q >> /Matrix [1 0 0 1 0 0] /Subtype /Form Q >> /Meta34 Do Q 0 0.279 m /Meta168 182 0 R 0 -0.003 l 45.663 0 0 45.783 90.337 581.171 cm q Worked example: Calculating the amount of product formed from a limiting reactant. BT >> 253 0 obj << /Resources << endobj 1.047 -0.003 l >> Q 0000041077 00000 n >> 0 0 l 0.458 0 0 RG >> [(S )-23(\(s\))] TJ /Meta109 Do Q /Matrix [1 0 0 1 0 0] /Font << q 0000028557 00000 n >> [(+)] TJ /Length 62 /Meta9 17 0 R 1 g q BT /Meta130 144 0 R Q /Resources << /Font << Q Q stream /Type /XObject stream /F1 6 0 R 122 0 obj << /Meta58 Do /F1 6 0 R /Matrix [1 0 0 1 0 0] 0000034942 00000 n q 0 g endstream 0 w 1.047 -0.003 l Q /F1 6 0 R W* n 0 0.279 m 9.507 -0.003 l /Font << /Meta1 7 0 R /F3 25 0 R Q /Type /XObject q Q 158 0 obj << 92 0 obj << /F1 0.217 Tf 0 g /F1 6 0 R >> 45.663 0 0 45.783 448.676 365.866 cm BT q 9.507 2.074 l 1.047 -0.003 l -0.007 Tc /Meta135 149 0 R >> Q 0 G 8.527 0.087 TD /Length 124 endstream Q stream q 0 g /F1 0.217 Tf 0000012008 00000 n endobj trailer q Q /Meta90 104 0 R 1 g stream 0.531 -0.003 l 45.289 0 0 45.274 81.303 383.934 cm /F1 0.217 Tf 0.015 w 0000028050 00000 n Q >> Q q 0 0.279 m Multiple-choice questions may continue on the next column or page – find all choices before answering. /Subtype /Form ] 45.289 0 0 45.274 81.303 383.934 cm 1.047 0.279 l Suppose it’s pancake day and you’re having friends over, so you look up the following recipe on the internet: 5 pancakes aren’t really a lot tho… 0000035429 00000 n 0 g 0000039819 00000 n >> Q 1 g >> /BBox [0 0 9.507 1.562] 0000016316 00000 n 0.799 0.418 TD /Resources << endstream q q q endobj /F1 6 0 R 0000066336 00000 n -0.002 Tc W* n endstream /Type /XObject 0.001 Tc /Resources << /Meta108 122 0 R /Subtype /Form 0 g endstream stream 1 g 0 -0.003 l /Length 66 [( Al\(N)] TJ /Subtype /Form Q 0 -0.003 l 1.047 0.279 l 0.314 -0.003 l Q /I0 70 0 R /FormType 1 endobj /Meta60 Do W* n /Subtype /Form 45.663 0 0 45.783 179.922 475.777 cm /BBox [0 0 9.507 1.562] Q [(w)-18(i)19(th)] TJ /Subtype /Form 0 0.279 m /F1 6 0 R BT BT endobj /BBox [0 0 9.507 1.795] >> 0.458 0 0 RG /Type /XObject 0 -0.003 l /F1 6 0 R If you looking for special discount you'll need to searching when special time come or holidays. endobj q 9.775 -0.003 l endstream /FormType 1 Q /Subtype /Form /Type /Pages 0.564 G W* n endstream /Meta245 Do W* n BT 0 -0.003 l /Font << stream /Font << 1.877 0.981 TD /Subtype /Form Q In an experiment, 3.25 g of NH 3 are allowed to react with 3.50 g of O 2. Multiple Choice (Choose the best answer.). q After you answer each multiple-choice question, you will note the 0 0.279 m q Q 0 g 0 g >> 0.015 w endobj 45.289 0 0 45.354 81.303 130.236 cm /Meta205 Do 0 g 133 0 obj << /Resources << /Type /XObject Q stream /Subtype /Form q /Meta74 88 0 R q 45.663 0 0 45.783 90.337 475.777 cm 45.413 0 0 45.783 523.957 441.9 cm q 0 0.279 m Q /BBox [0 0 0.263 0.279] q >> /F1 0.217 Tf 90 0 obj << >> 0 g >> Q /F1 0.217 Tf >> q 0 1.795 m /Subtype /Form /FormType 1 /Matrix [1 0 0 1 0 0] 0 G -0.002 Tc /Resources << 0 g -0.002 Tw /Meta68 82 0 R q 0 w 0 g /F1 0.217 Tf >> endstream 0 -0.003 l /Length 66 endobj /Subtype /Form 0 -0.003 l 0.7 mol of N 2. /Meta0 Do 0000026777 00000 n ET /Font << /F1 6 0 R /Length 67 >> /Subtype /Form >> 154 0 obj << /Type /XObject /Meta104 118 0 R BT /Type /XObject /F1 6 0 R q /Type /XObject 0 G q stream Usage: • If necessary, select “Full Screen” format from View menu (exit “Full Screen” format by pressing “Esc” key). Q [(3)] TJ /Resources << [(O)] TJ 0 G q /Matrix [1 0 0 1 0 0] q 0.047 0.083 TD /BBox [0 0 1.047 0.279] /FormType 1 93 0 obj << How many grams of NO are formed? 0.458 0 0 RG /Meta1 Do 45.663 0 0 45.783 269.506 475.777 cm /Subtype /Form /Meta215 229 0 R /Matrix [1 0 0 1 0 0] /Font << Q 4NH 3 +6NO --> 5N 2 + 6H 2 O (Remember, convert grams to moles, then divide each substance by the number of moles given as the coefficient from the balanced chemical equation). 0.531 -0.003 l /F1 6 0 R stream Q Q >> /Type /XObject >> q Q BT 0 0.279 m q stream 578.159 655.699 l /F1 6 0 R /Meta153 167 0 R 0.005 Tc 0 G 45.413 0 0 45.783 523.957 547.294 cm 1.047 -0.003 l endobj /Length 64 q 0.458 0 0 RG /BBox [0 0 9.507 1.511] >> q /Matrix [1 0 0 1 0 0] 75 0 obj << /Resources << /Meta190 204 0 R >> 45.663 0 0 45.783 179.922 112.169 cm 181 0 obj << endstream 0 g /Length 55 /Matrix [1 0 0 1 0 0] /Parent 1 0 R 0.314 0.279 l /BBox [0 0 1.047 0.279] /Meta17 Do 0000000121 00000 n 5. 2.574 1.036 TD q /BBox [0 0 9.507 1.511] /Type /XObject /Meta118 132 0 R 1.047 0.279 l 45.663 0 0 45.783 359.091 112.169 cm Q endobj /Meta247 Do 0 G q stream 1.047 -0.003 l /Subtype /Form 0000056846 00000 n q Q 0.015 w W* n /Type /XObject -0.007 Tc q 1.311 0.418 TD 0.001 Tc /Subtype /Form 0 g q /I0 Do 0 g Q 2.44 0.422 TD /Meta74 Do q 0 0.279 m 1.5 mol O2 x (2mol SO3/3mol O2) ... identify the limiting reactant that produces the least amount of product 4) to find the mass, multiply the number of moles of product formed (from the limitoing reactant) by the molar mass of the product. 0 g 0.002 Tw >> ET 82 0 obj << 3.555 0.752 TD /BBox [0 0 9.507 1.562] /Font << /FormType 1 1 g 0 G >> Q /FormType 1 0000012341 00000 n ET 0 g /FormType 1 q 45.287 0 0 45.452 36.134 673.014 cm /Resources << BT /FormType 1 Q 0.267 -0.003 l >> /Matrix [1 0 0 1 0 0] Q /FormType 1 >> [(S)-18(u)22(lfur and )23(oxy)21(gen re)20(act in a )18(combin)15(ation r)23(eactio)28(n to prod)25(uce )16(sulfur t)32(rioxide, )19(an en)16(vir)17(o)-15(n)20(men)21(t)-18(al)] TJ /Meta47 60 0 R 578.159 332.743 l Q endstream 0000015554 00000 n endstream /Meta192 Do >> /BBox [0 0 9.507 1.562] Q stream 0.267 0.279 l /FormType 1 45.287 0 0 45.783 194.978 365.866 cm /Resources << /FormType 1 endstream Q W* n 231 0 obj << /Length 571 >> /Subtype /Form Q Q q stream q endobj stream 0 G 0 g q >> 0 g >> q ET 0000010560 00000 n [( \()20(s\))] TJ 0.015 w BT 0 0.279 m /Length 122 q 0 0.279 m 0.564 G 0.004 Tw 1.047 0.279 l Q /BBox [0 0 0.263 0.279] 0000071016 00000 n q 0 -0.003 l 1.047 0.279 l /Subtype /Form /Meta71 85 0 R 0 -0.003 l q stream /Length 122 /BBox [0 0 9.507 1.795] ET 55 0 obj << q q /Meta103 Do 0000050227 00000 n >> Q stream BT 0.002 Tc q ET /Meta239 253 0 R /Matrix [1 0 0 1 0 0] /Resources << 4. 0.458 0 0 RG 0 0.279 m /Font << [(2S \(s\))] TJ 2.74 0.705 TD 0 -0.003 l q >> /Subtype /Form /Font << endstream endstream stream q Q /Meta103 117 0 R endobj q /FormType 1 1.047 -0.003 l /Subtype /Form 186 0 obj << endobj Q W* n /Font << /Resources << 0 0.279 m 74 0 obj << Q ET endobj Q 1 g /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] >> 210 0 obj << 1.047 -0.003 l /Meta97 111 0 R 45.287 0 0 45.783 105.393 245.416 cm 0.267 -0.003 l q q 0 G >> /F1 6 0 R q 0 g /Meta119 133 0 R /Matrix [1 0 0 1 0 0] 0000070454 00000 n q /Meta166 Do /BBox [0 0 9.507 1.511] 1 g 0 0.083 TD 247 0 obj << 0000031966 00000 n The other reactants are partially consumed where the remaining amount is considered "in excess". BT 0 g q endstream /Meta95 109 0 R endobj /Ascent 976 0000068599 00000 n endstream >> >> 6.051 0.087 TD 1.047 0.279 l q /Meta129 143 0 R /F1 0.217 Tf 218 0 obj << Q q 0 g 0.564 G q q /Subtype /Form /Meta216 Do >> 0000005658 00000 n /FormType 1 q /Meta123 137 0 R /Meta52 65 0 R 0 0.279 m [(O)] TJ -0.007 Tc 45.289 0 0 45.354 81.303 130.236 cm 0 0.083 TD /Length 122 /Meta163 177 0 R /BBox [0 0 0.531 0.279] /Font << Q 0 w >> /Type /XObject q 45.663 0 0 45.783 448.676 581.171 cm Q 0 G stream /Subtype /Form 0 0.279 m 11.968 0.279 l 6.547 0.422 TD /Meta130 Do W* n [(S)-18(o)20(lid alu)25(minu)19(m and g)22(as)17(eous ox)26(ygen rea)23(ct in a )26(co)-25(mb)21(ination r)26(eact)25(i)-16(o)20(n to prod)25(uce )16(alu)15(minu)19(m oxide)20(:)] TJ stream /Matrix [1 0 0 1 0 0] Q 201 0 obj << /Matrix [1 0 0 1 0 0] /Meta102 Do stream stream /F1 6 0 R /Resources << /Matrix [1 0 0 1 0 0] 0.564 G /Type /XObject /Length 122 Q endobj ET endobj 0.267 0.279 l 1.047 -0.003 l 9.775 -0.003 l >> Q [( 3AgC)-23(l \(s)-22(\))] TJ endstream Q >> 0.267 0.279 l 2.192 0.752 TD endobj 0.005 Tc 25 0 obj << 128 0 obj << Q Q Q /Type /XObject /Meta175 Do /Resources << >> /Meta44 57 0 R BT 223 0 obj << /BBox [0 0 9.507 1.511] Q The equation requires 3 moles of HCl for every mole of Al. /Font << /Subtype /Form This is the currently selected item. stream 0 g >> 0 G 0 -0.003 l 0000023928 00000 n LIMITING REAGENT PROBLEMS Name_____ MULTIPLE CHOICE. /Meta75 Do /Subtype /Form >> 0 g 0000048457 00000 n /F4 32 0 R Zn b) How many grams of ZnS will be formed? EŒ'.äPvÚxP4èâ㤢&N.1q I)U5u M-S3sK+gW7wO¯à�Ğ°ğˆÈ¨ä”Ô´ôŒÌ¬â’Ò²òŠÊªæ–Ö¶ö�ήI“§L�6}ÆÌY‹/YºlùŠ•«6m޲uÛö;w:|äè±ã'N�ºtùÊÕk×oܼõğÑã'OŸ=ñòÕÇOŸ¿|ıöıÇÏ_ÿo1p€ücÏğïŸÆ¢®!€Öÿ¿ Áh®endstream 1.047 0.279 l stream >> >> 0.458 0 0 RG /Meta127 Do >> /F1 6 0 R Q ET 3.24 0.989 TD >> 3.771 0.367 TD 0.267 -0.003 l /F1 0.217 Tf /Matrix [1 0 0 1 0 0] 0.015 w >> [(1)51(.7)] TJ >> q /Length 55 -0.012 Tc 0.267 -0.003 l Q 160 0 obj << 0.066 0.083 TD ET ET W* n /F1 0.217 Tf endstream /Subtype /Form W* n ET q /Meta4 Do stream Q >> Q 193 0 obj << >> endobj /Matrix [1 0 0 1 0 0] q /Resources << /Meta172 186 0 R /Meta241 255 0 R endstream 108 0 obj << -0.002 Tc /Subtype /Form 45.289 0 0 45.313 81.303 599.238 cm The lowest value is the LR and the highest value is the ER. /Matrix [1 0 0 1 0 0] /Type /XObject >> q /Meta206 Do /Font << >> /Meta22 Do 0000068092 00000 n Q q /Matrix [1 0 0 1 0 0] 0.458 0 0 RG Q 0 0.279 m /F1 0.217 Tf /Meta156 Do /Font << /Meta157 171 0 R Q /Meta199 213 0 R 0 g stream endstream q /F3 0.217 Tf BT >> /Font << Q Q /Meta212 Do BT /Meta115 129 0 R /Meta169 Do 0000063469 00000 n >> 0 -0.003 l Q /Meta146 Do 0 -0.003 l Q endobj /FormType 1 ET 0000056601 00000 n /Font << /BBox [0 0 0.263 0.279] /Font << endstream 0000002668 00000 n >> W* n /Type /XObject /Meta70 Do q /Meta205 219 0 R Q stream 0.458 0 0 RG 0 1.562 m q /Subtype /Form >> 0 g stream /F1 6 0 R 0.564 G /BBox [0 0 9.507 1.795] /Type /XObject q 0 w Q 206 0 obj << Q W* n Q q /Type /XObject /F1 0.217 Tf /Meta67 81 0 R q /F1 6 0 R stream /Resources << q [<000F>] TJ /Type /XObject >> /Font << 3. 45.287 0 0 45.273 36.134 694.845 cm ET /Length 67 /F1 0.217 Tf stream 0 0.279 m endobj 0.458 0 0 RG q /BBox [0 0 1.047 0.279] stream /Matrix [1 0 0 1 0 0] q 0000056339 00000 n endstream /Length 122 stream stream >> q q /Meta41 Do stream BT /Type /XObject /FormType 1 /F1 0.217 Tf 0.267 0.279 l q q /Subtype /Form /FormType 1 Q q >> -0.002 Tc /F1 6 0 R 183 0 obj << endobj /Meta59 73 0 R /BBox [0 0 0.263 0.279] /F1 0.217 Tf /Type /XObject q W* n 0 0.279 m /Resources << BT 0 G Q 1.047 0.279 l W* n stream Q endstream endobj /Font << >> 1 g 0 g 0000068861 00000 n 0000009535 00000 n /W [ /Matrix [1 0 0 1 0 0] /FormType 1 Q /Length 55 endobj q 169 0 obj << /Length 80 q 113 0 obj << /Subtype /Form q 45.289 0 0 45.274 81.303 383.934 cm /FormType 1 stream q q 45.663 0 0 45.783 269.506 112.169 cm 0000054321 00000 n [(0)19(. 0 g 0 g Q >> 0000001988 00000 n 45.289 0 0 45.313 81.303 599.238 cm /F1 0.217 Tf 0 G /F1 6 0 R 45.663 0 0 45.783 359.091 475.777 cm q 2.078 0.753 TD Q /F1 0.217 Tf /Font << BT Q Q /BBox [0 0 0.263 0.279] >> endstream q 203 0 obj << /Meta13 Do Q >> /BBox [0 0 0.263 0.279] 0 G 173 0 obj << Q 0 g Q q q /Matrix [1 0 0 1 0 0] 0 g /Meta236 Do endstream 0.564 G >> q endobj >> >> 0000069101 00000 n 45.287 0 0 45.783 194.978 112.169 cm /Meta157 Do /Meta196 210 0 R 1.047 0.279 l >> -0.003 Tc /Font << >> 161 0 obj << /Meta170 184 0 R 15 [988] [(O)] TJ q 45.287 0 0 45.783 374.147 581.171 cm /Meta234 Do Q /Resources << /F1 0.217 Tf >> q [(0)-16(.27)] TJ >> Q /FontName /LGVEOV+TestGen ET 45.663 0 0 45.783 90.337 112.169 cm /Matrix [1 0 0 1 0 0] /FormType 1 Q endobj 0 0.279 m q stream /Meta245 259 0 R q /Subtype /Form [( \(g\))] TJ /FormType 1 0 G q [( 2)16(S)] TJ 69 0 obj << endobj 0000005913 00000 n 78 0 obj << /Type /XObject /Meta8 Do /Font << 0 -0.003 l Q [( 2)] TJ /Meta224 Do q 0 G Q ET Q W* n 0 g endobj /BBox [0 0 9.507 1.511] /Meta237 251 0 R stream The coefficients in a chemical equation represent the a. masses, in grams, of all reactants and products. /Length 54 Q /Font << ET 45.289 0 0 45.287 81.303 263.484 cm /Meta173 187 0 R [(wate)17(r?)] 0 g /F1 0.217 Tf Q ET 0000013811 00000 n 43 0 obj << ET q /BBox [0 0 0.263 0.279] [(0)-16(.0)-29(162)] TJ Q W* n endobj q >> /Meta133 147 0 R stream 45.289 0 0 45.287 81.303 263.484 cm endobj endstream q q endobj 0000020150 00000 n /Meta194 Do /Subtype /Form 0 G 0.564 G 0 1.599 TD 45.663 0 0 45.783 448.676 475.777 cm q /Type /XObject /Resources << 0 0.279 m 0 -0.003 l /FormType 1 0 -0.003 l Q q /Resources << >> q >> W* n q Q 0.564 G 34 0 obj << /Subtype /Form 0 0.279 m 0.814 1.032 TD q /BBox [0 0 1.047 0.279] endobj /Matrix [1 0 0 1 0 0] /Meta148 162 0 R Q q q 5.669 0.418 TD >> 0 0.279 m /FormType 1 Q 0 g >> /Font << >> 226 0 obj << q 0.314 -0.003 l 0.267 0.279 l /Resources << endstream Q Q >> /Subtype /Form /Meta96 110 0 R 0 -0.003 l BT W* n Q 123 0 obj << Unit 3 Quiz--Limiting Reactants: Multiple Choice (Choose the best answer.)

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Kiedy warto wykonać wampirzy lifting twarzy?

Lifting to zabieg najczęściej kojarzony z inwazyjną procedurą chirurgii plastycznej. Jednak można przeprowadzić go także bezinwazyjnie – wystarczy udać się do dobrego gabinetu medycyny estetycznej. Tam można wykonać zabieg wampirzego liftingu, który obecnie cieszy się bardzo dużym powodzeniem.